"If Nobody sees it, it didn't Happen"
Hackthebox: emdee five for life challenge is based on python scripting as how fast a request can be sent and stuff can be automated. For this challenge, I had to go through the forum threads
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Hackthebox Grammar is based on the MAC [Message Authentication Code] and how PHP handles the MAC strings also called as typejuggling. PHP tries to evaluate the MAC based on the starting strings, if it is
Hackthebox: I know Mag1k is based on Oracle padding attack. Padding Oracle is based on decryption of the cipher text based on existing cipher information. Padding Oracle allows you to decrypt the encrypted code.Moreover, we
XSS stands for Cross-Site Scripting, which is one of the attacks type on the Websites. In this article, I will be using https://xss-game.appspot.com to demonstrate how you can check for XSS bugs in different input
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Node CTF is available at:Â https://www.vulnhub.com/entry/node-1,252/ This Vulnerable machine Node is based on the new technologies and how we can hack into them. It uses Node Express server Json and hadoop. There are many ways to
Overthewire Natas Level 25 – 26 is based on directory traversal. The code have many restrictions because it sanitizes the user input and makes it harder for us to get the password. Let’s see how
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Overthewire Natas 25 Level is based on strcmp() function vulnerability. Generally, strcmp() is used to compare two strings together, We need to generate some kind of error here so we can obtain the password for
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Overthewire natas level 23 – 24 is also based on PHP GET request parameter tampering. We have to carry out the injection in such a way that it fits both the conditions of the code.
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Overthewire natas level 22 – 23 is the easiest of all levels, We just have to send a GET request as “/?revelio” to reveal the admin password. This code for this level looks like this:
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Overthewire natas level 21 -22 is also like the last level but, there is Key and value pair as the input values. All we need to do is inject admin=1 as one of the key->value
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